Question

[(2x+3) + (x+5)]²+[(2x+3-(x+5)]²=10x²+92

Answer 1

$((2x + 3) + (x + 5)) {}^{2} + ((2x + 3) - (x + 5)) {}^{2} = 10x {}^{2} + 92 \\ (2x + 3 + x + 5) {}^{2} + (2x + 3 - x - 5) {}^{2} = 10 {}^{2} + 92 \\ (3x + 8) {}^{2} + (x - 2) {}^{2} = 10x {}^{2} + 92 \\ 9x {}^{2} + 64 + 48x + x {}^{2} + 4 - 4x = 10x {}^{2} + 92 \\ 10x {}^{2} + 44x + 68 = 10x {}^{2} + 92 \\ 10x {}^{2} + 44x + 68 - 10x {}^{2} - 92 = 0 \\ 44x - 24 = 0 \\ 44x = 24 \\ x = \frac{24}{44} \\ x = \frac{6}{11} .......answer$