2x-3 y+1=0,3 x+4 y-5=0, by elimination method to get answer
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Let,
2x-3y+1 --------- 1 eq.
and x+4y-5=0 ------ 2 eq.
Step-by-step explanation:
By taking 1 eq. we get
= 2x-3y+1 = 0
= 2x-3y= -1
= 2x = 3y-1
= x = (3y -1) / 2
Putting the value of x in 2 eq. , we get
=(3y-1) /2 + 4y=5
multiplying eq by 2
3y-1 +8y = 5
11y = 6
y = 6/11
putting value of y in 1 eq
2x -3(6/11) = -1
2x-18/11= -1
2x = (-11+18) / 11
2x = 7/11
x = 7/22
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