2x/3-y/2+1/6=0 and x/2+2y/3=3 then value of x and y = ?
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2x/3-y/2+1/6=0 and x/2+2y/3=3
2x/3-y/2+1/6=0
4x-3y+1=0
4x-3y=-1
x/2+2y/3=3
3x+4y=18*4
4x-3y=-1*3
12x+16y=72
12x-9y=-3
25y=75
y=3
substitute y value above equation we get x value
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