Question

2x-34-42 = 0
then find
8^3-27y^3-64z^3​

Answer 1

Answer:

72 xyz

Step-by-step explanation:

If x + y + z = 0 then x3 + y3 + z3 = 3xyz 8x3 – 21y3 – 64z3 = (2x)3 + (-3y)3 + (-4z)3 = 3 x (2x) x (-3y) x – 4z = 72 xyz

Hope it helps:)

Answer 2

yett nhi mla

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