Question

2x^-3mx+10=0 is 6? For what value of m the sum of rrot of equation​

Answer 1

Answer:

$\bf\red{Answer-}$

$\huge\boxed{\fcolorbox{red}{Yellow}{x=6 given }}$

$\ \implies$

$2 {x}^{2} - 3mx + 10 = 0$

$x = 6$

$2( {6}^{2} ) - 18m + 10 = 0$

$36 \times 2 - 18m + 10 = 0$

$72 - 18m + 10 = 0$

$82 - 18m = 0$

$m=82/18$

$m=41/9$

Answer 2

$\bf\red{Answer-}$

If - 2 and 5 are roots, then

-2+5 = - (-3m)/2 which gives m = 2

And,

-2*5 = 5n/2 which gives n = - 4