2x^+3x-6 is a quadratic equation so find it's roots?
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Hey, here is your answer, <br> 2x^2 + 3x - 6 = 0 a = 2 , b = 3 , c = -6 Substitute the values in the equation , X = -b +/- √b^2 - 4ac / 2a X = -3 +/- √9-4(2)(-6) / 2(2) X = -3 +/- √9+48 / 4 X = -3 +/- √57 / 4 X = -3+√57/4 , -3-√57/4 Hope it helps you!
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2X² + 3X - 6
It is in the form of ax² + bx + c . So it is a quadratic polynomial.
2X² + 3x - 6
Here,
a = 2 , b = 3 and C = -6.
Alpha = -b + √d /2a and beta = -b - √d/2a
alpha = -3 + √(3)² - 4×2×-6 /2×2 and beta = -3 - √(3)² - 4 × 2 × -6 /2 × 2
alpha = -3 + √9+48 /4 and beta = -3 - √9+48/4
alpha = -3 + √57 /4 and beta = -3 - √57/4.
It is in the form of ax² + bx + c . So it is a quadratic polynomial.
2X² + 3x - 6
Here,
a = 2 , b = 3 and C = -6.
Alpha = -b + √d /2a and beta = -b - √d/2a
alpha = -3 + √(3)² - 4×2×-6 /2×2 and beta = -3 - √(3)² - 4 × 2 × -6 /2 × 2
alpha = -3 + √9+48 /4 and beta = -3 - √9+48/4
alpha = -3 + √57 /4 and beta = -3 - √57/4.
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