√2x+√3y=0 √3x-√2y=0 by elimination method
Answers
Answer:
x=0
y=0
Step-by-step explanation:
Given pair of linear equations is
√2 x + √3 y = 0 …(i) And
√3x - √2y = 0 …(ii)
On multiplying Eq. (i) by √3 and Eq. (ii) by √2 to make the coefficients of y equal, we get the equation as
√6x + √9 y = 0 …(iii)
√6x - 2y = 0 …(iv)
On adding Eq. (iii) and (iv), we get
5y = 0
⇒ y = 0
On putting y = 0 in Eq. (i), we get
√2 x + √3 y = 0
⇒ √2 x – √3 (0) = 0
⇒ – √2 x = 0
⇒ x = 0
Hence, x = 0 and y = 0 , which is the required solution
Answer:
Answer:
x=0
y=0
Step-by-step explanation:
Given pair of linear equations is
√2 x + √3 y = 0 …(i) And
√3x - √2y = 0 …(ii)
On multiplying Eq. (i) by √3 and Eq. (ii) by √2 to make the coefficients of y equal, we get the equation as
√6x + √9 y = 0 …(iii)
√6x - 2y = 0 …(iv)
On adding Eq. (iii) and (iv), we get
5y = 0
⇒ y = 0
On putting y = 0 in Eq. (i), we get
√2 x + √3 y = 0
⇒ √2 x – √3 (0) = 0
⇒ – √2 x = 0
⇒ x = 0
Hence, x = 0 and y = 0 , which is the required solution