2x+3y=0 3x+4y=5 by cross multiplication method
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2
2x + 3y= 0 ……..(1) 3x + 4y = 5 …….(2) Let us use elimination method to solve the given system of equations. Multiply (1) by 4 and (2) by 3. And subtract both the equations. From (1), y = -10
Answered by
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Answer:
2x+y−5=0
3x+2y−8=0
Using cross multiplication method, we get
b
1
c 2
−b
2
c
1
x
=
c
1
a
2
−c
2
a
1
y
=
a
1
b
2
−a
2
b
1
1
2
x
=
+1
y
=
1
1
So, x=2 and y=+1
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