Math, asked by Pihusingh22, 10 months ago

2x+3y=0 3x+4y=5 by cross multiplication method

Answers

Answered by snehamittal220
2

2x + 3y= 0 ……..(1) 3x + 4y = 5 …….(2) Let us use elimination method to solve the given system of equations. Multiply (1) by 4 and (2) by 3. And subtract both the equations. From (1), y = -10

Answered by Anonymous
0

Answer:

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2x+y−5=0

3x+2y−8=0

Using cross multiplication method, we get

b

1

c 2

−b

2

c

1

x

=

c

1

a

2

−c

2

a

1

y

=

a

1

b

2

−a

2

b

1

1

2

x

=

+1

y

=

1

1

So, x=2 and y=+1

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