Question

2x+3y=0
3x+4y=5
By elimation method

Answer 1

Answer:

$\bigstar$ x = 15 and y = -10

Step-by-step explanation:

2x+3y=0 -------- eq (1)

3x+4y=5 -------- eq (2)

→ Multiply equation (1) by 3 and equation (2) by 2

Now the equations becomes →

6x + 9y = 0

6x + 8y = 10

__________ [Subtract both the equations]

(-) (-) (-)

__________

0 + y = -10

__________

→y = -10

$\large{\red{\underline{\tt{y\:=\:-10}}}}$

$\bigstar$ Now substituting the value of y in equation (1)

→2x + 3y = 0

→2x + 3(-10) = 0

→2x - 30 = 0

→2x = 30

→x = $\dfrac{30}{2}$

→x = 15

$\large{\red{\underline{\tt{x=15}}}}$

$\rule{200}2$