Question

√2x+√3y=0,√3x-√8y=0
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Answer 1

$\Large{\underline{\underline{\bf{Solution:-}}}}$

$\rm{ \sqrt{2x} + \sqrt{3y} =0.......(i)}$

$\rm{ \sqrt{3x} - \sqrt{8y} =0..........(ii)}$

${\bold{\underline{\underline{From\: equation\: (i)\: , we \: obtain}}}}$

$\rm{x = \frac{ \sqrt{ - 3y} }{ \sqrt{2} } ........(iii)}$

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${\bold{\underline{\underline{Substituting\: this \: value\: in\: equation\: (ii)\: , we \: obtain}}}}$

⟾$\rm{ \sqrt{3} [\frac{ \sqrt{3y} }{ \sqrt{2} }] - \sqrt{8y} = 0}$

⟾$\rm{\frac{ - 3y}{ \sqrt{2} } - 2 \sqrt{2y} = 0}$

⟾$\rm{y [\frac{ - 3}{ \sqrt{2} } - 2 \sqrt{2} ] = 0}$

⟾$\rm{y=0}$

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${\bold{\underline{\underline{Substituting\: this \: value\: in\: equation\: (iii)\: , we \: obtain}}}}$

⟾$\rm{ x = \frac{ \sqrt{3(0)} }{ \sqrt{2} } }$

⟾$\rm{x=0}$

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${\rm{\boxed{\boxed{x=0}}}}$

${\rm{\boxed{\boxed{y=0}}}}$

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$\Large{\underline{\underline{\bf{Thanks}}}}$