Question

√2x+√3y=0 , √3x-√8y=0
linear equation
pls help..​

Answer 1

$\sqrt{2} x + \sqrt{3} y = 0 - - - - 1 \\ \\ \sqrt{3} x - \sqrt{8} y = 0 - - - - 2 \\ \\ from \: equation - 1 \\ \\ \sqrt{2} x = - \sqrt{3} y \\ \\ x = - \frac{ - \sqrt{3}y }{ \sqrt{2} } \\ \\ substitute \: x \: in \: eq - 2 \\ \\ \sqrt{3} x - \sqrt{8} y = 0 \\ \\ \sqrt{3} ( \frac{ - \sqrt{3}y }{ \sqrt{2} } ) - \sqrt{8} y = 0 \\ \\ - 3y - \sqrt{16} y = 0 \\ \\ - 3y - 4y = 0 \\ \\ - 7y = 0 \\ \\ y = \frac{0}{7} \\ \\ y = 0 \: and \: x = 0 \\ \\ mark \: me \: as \: brainliest$