√2x+√3y=0
√3x-√8y=0
solve by substitution method
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Answer:
check attachment heheheh its right
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Step-by-step explanation:
√3x=√8y
x=√8y/√3
put in first equation
√2×√8y/√3+√3y=0
(4y+3y)/√3=0
7y=0,y=0
x=0
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