Question

√2x + √3y=0
√3x -√8y=0
solve the following pair by substitution method​

Answer 1

Answer:

√2x + √3y=0

so x = -√3y / √2

now √3x -√8y=0 putting value of x in equation.

we get

(√3 * -√3y / √2) - √8y = 0

(-3y / √2) - √8y = 0

so y = 0

now put the value of y in x equation we x= 0 .

so x = y = 0

Step-by-step explanation: