Question

√2x-√3y=0, √3x-√8y=0 substitution

Answer 1

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Answer 2

Given :

√2x-√3y=0, √3x-√8y=0

To Find : Solve

Solution:

Equation 1:$\sqrt{2}x-\sqrt{3}y=0$

Equation 2: $\sqrt{3}x-\sqrt{8}y=0$

Substitute the value of x from equation 1 in equation 2

$\sqrt{3} (\frac{\sqrt{3}y}{\sqrt{2}})-\sqrt{8}y=0\\\frac{3y}{\sqrt{2}}-\sqrt{8}y=0$

y=0

Substitute the value of y in 1

$\sqrt{2}x-\sqrt{3}y=0\\\sqrt{2}x-\sqrt{3}(0)=0$

x=0

Hence The value of x and y is 0