Question

2x+3y=0 ;9x-41=16
solve by
by elimination method.​

Answer 1

Answer:

Given : 2x + 3y = 0. eqn no.1

9x - 41 =16. eqn no.2

Step-by-step explanation:

From eqn no. 2

9x - 41 = 16

9x = 16 + 41

9x = 57

x = 57/9 = 19/3

Putting x = 19/3 in eqn no. 1,

2(19/3) + 3y = 0

38/3 + 3y = 0

3y = 38/3

y = 38/9

Answer 2

Answer:

-4

Step-by-step explanation:

9x-41=16

9x=16+41

9x=57

x=57/9

=6.333 I. e 6

NOW,

by putting the value of x=6 in 2x+3y=0

2×6+3y=0

12+3y=0

3y=0-12

y= -12/3

y= -4