Question

√2x-√3y=0 and √5x+√2y=0. Use elimination method

Answer 1

Hi friends...
here is the solution

√2x-√3y =0
multiplying by √2
4x- √6y = 0 ....................eq.(1)

√5x+√2y =0
multiplying by √2
√15x +√6y = 0 ...............eq.(2)

from eq.(1)+(2),

4x +√15x = 0
=> x = 0
putting the value of x in the eq(1)
(4×0) - (√6y) =0
=> y = 0

Hence the answer is x = 0 & y = 0
___________________________
Hope it helps........

Answer 2

Given pair of linear equations is √2 x – √3 y = 0 …(i)

And √5 x + √2 y = 0 …(ii)

On multiplying Eq. (i) by √2 and Eq. (ii) by √3 to make the coefficients of y equal, we get the equation as

2x – √6 y = 0 …(iii)

√15 x + √6 y = 0 …(iv)

On adding Eq. (iii) and (iv), we get

2x – √6 y + √15 x + √6 y = 0

⇒ 2x + √15 x = 0

⇒ x(2 + √15) = 0

⇒ x = 0

On putting x = 0 in Eq. (i), we get

√2 x – √3 y = 0

⇒ √2(0) – √3 y = 0

⇒ – √3 y = 0

⇒ y = 0

Hence, x = 0 and y = 0 , which is the required solution.