2x - 3y=0
and xy=
16 and
find 8x³-27y³
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Answer:8x^3 - 27y^3 = 3880
Step-by-step explanation:
2x - 3y = 10 ------------- (i)
On cubing both sides
=> (2x - 3y)^3 = (10)^3
=> (2x)^3 - (3y)^3 - 3 × 2x × 3y (2x - 3y) = 1000
=> 8x^3 - 27y^3 - 18xy (10) = 1000
=> 8x^3 - 27y^3 - 180xy = 1000
=> 8x^3 - 27y^3 - 180 × 16 = 1000
=> 8x^3 - 27y^3 - 2880 = 1000
=> 8x^3 - 27y^3 = 1000 + 2880
=> 8x^3 - 27y^3 = 3880
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