Math, asked by bhosaletanmay0908, 4 months ago

2x+3y+1=0,3x-2y-5=0 solve tis example by cramers rule​

Answers

Answered by Anonymous
3

Answer:

D=2 3

3 -2

D=(2x-2)-(3x3)

D= -4-9

D= -13

Dx=(-1x-2)-(5x3)

Dx = 2-15

Dx= -13

Dy=(2x5)-(3x-1)

Dy=10+3

Dy=13

x=Dx/D

x= -13/-13

x=1

y=Dy/D

y=13/-13

y= -1

(x, y)=(1,-1) is the solution

hope it help you

Answered by Anonymous
3

Answer:

Question :-

2x+3y+1=0 , 3x-2y-5=0

solve by cramer's rule

Required Answer :-

D= 2 3

3 -2

D=(2 x -2) - (3 x 3)

D= -4-9

D= -13

Dx = (-1 x -2) - (5 x 3)

Dx = 2-15

Dx = -13

Dy = (2x5) - (3x-1)

Dy = 10 + 3

Dy = 13

x =Dx/D

x = -13/-13

x = 1

y = Dy/D

y = 13/-13

y= -1

(x, y) = (1,-1) is the solution

hope it help you :)

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