2x-3y=-1 और 3×+7=10 को हल kro
Answers
Answer:
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Step 1. Enter the equations.
[1]
2
x
+
3
y
=
7
[2]
3
x
+
4
y
=
10
Step 2. Multiply each equation by a number to get the lowest common multiple for the coefficients of one variable.
Multiply Equation 1 by
3
and Equation 2 by
2
.
[3]
6
x
+
9
y
=
21
[4]
6
x
+
8
y
=
20
Step 3. Subtract Equation 4 from Equation 3.
[5]
y
=
1
Step 4. Substitute Equation 5 in Equation 1.
2
x
+
3
y
=
7
2
x
+
3
×
1
=
7
2
x
+
3
=
7
2
x
=
4
x
=
2
Solution: The solution that satisfies both equations is
(
2
,
1
)
.
Check: Substitute the values of
x
and
y
in each Equation.
2
x
+
3
y
=
7
2
×
2
+
3
×
1
=
7
4
+
3
=
7
7
=
7
3
x
+
4
y
=
10
3
×
2
+
4
×
1
=
10
6
+
4
=
10
10
=
10
Step-by-step explanation:
2x-3y=-1.........equation 1st × 3
3x+7y=10.......equation 2nd × 2.....by elimination.method
6x-9y=-3.......eqn.....3rd
6x+14y=20.....eqn...4th.....by substract..
-23y=-23
y = 1..