Question

2x+3y=-1
$|?|$
x - y = 2​

Answer 1

Do u want the solution of these 2 equations??

Answer 2

Answer:

since

2x3yy′+(1−y2)(x2y2+y2−1)=0

then we have

2x3yy′=(y2−1)2+(y2−1)x2y2=(y2−1)2+(y2−1)x2(y2−1)+x2(y2−1)

so

x3(y2−1)′=(y2−1)2+(y2−1)2x2+x2(y2−1)

let y2−1=u,then we have

dudx=(1x+1x3)u2+ux

this is Bernoulli equation

−d(1/u)dx=1x⋅1u+1x3+1x