2x-3y = -10
3x+3y = 0
solve the above equation
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2x-3y = -10 ....(1)
3x+3y = 0 ....(2)
By solving (1) and (2) we get,
5x = -10
x = -10/5
x = -2
sub, x = -2 in (1)
2(-2)-3y = -10
-4-3y = -10
-3y = -10+4
-3y = -6
y = -6/-3
y = 2
#Hassan
3x+3y = 0 ....(2)
By solving (1) and (2) we get,
5x = -10
x = -10/5
x = -2
sub, x = -2 in (1)
2(-2)-3y = -10
-4-3y = -10
-3y = -10+4
-3y = -6
y = -6/-3
y = 2
#Hassan
Answered by
0
I hope you understand my answer
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