Question

2x+3y=10 and 5x -3y=6 find x and y

Answer 1

Answer:

$2x + 3y = 10$

$x = \frac{10 - 3y}{2}$

$5 (\frac{10 - 3y}{2} ) - 3y = 6$

$\frac{50 - 15y}{2} - 3y = 6$

$50 - 15y - 6y = 12$

$50 - 21y = 12$

$- 21y = - 38$

$y = \frac{38}{21}$

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$x = \frac{10 - 3y}{2}$

$\frac{10 - 3 (\frac{38}{21} )}{2}$

$\frac{10 - \frac{114}{21} }{2}$

$\frac{210 - 114}{42}$

$x = \frac{96}{42} = \frac{48}{21} = \frac{16}{7}$

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Answer 2

Answer:

2x+3y=10---------------Equation 1

5x -3y=6---------------Equation 2

From eq 1 and eq 2 we get,

7x = 16

x = 16/7

From eq 1 we can get the value of y ,

2(16/7)+3y=10

32/7 + 3y = 10

3y = 10 - 32/7

3y = ( 70 - 32 )/7

3y = 38/7

y = 38/7 ÷ 3

y = 38/7 x 1/3

y = 38/21

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