Math, asked by vanshmistry, 10 months ago

2x+3y=10 and 7x+5y=24 by elimination method I need right now​

Answers

Answered by amansharma264
2

Answer:

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Answered by Vamprixussa
4

Given equations

2x+3y=10--(1)\\7x+5y=24--(2)

Multiplying the first equation by 7, we get,

14x+21y=70--(3)

Multiplying the first equation by 2, we get,

14x+10y=48--(4)

Solving (3) and (4), we get,

14x+21y=70\\\underline{14x+10y=48}\\\underline{\underline{11y=22}}\\\implies y = 2

Substituting y = 2 in the first equation , we get,

2x+3(2)=10\\\implies 2x+6=10\\\implies 2x=10-6\\\implies 2x=4\\\implies x = 2

\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \ y \ are \ 2 \ and \ 2 \ respectively}}}}}}}}}}}}}}

                                                           

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