Question

2x -3y = 10, and xy =16, find 8x^3- 2y^3

Answer 1

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According to question:

$2x - 3y = 10$

$x \times y = 16$

$x = \frac{16}{y}$

$2 \times \frac{16}{y} - 3y = 10$

$\frac{32}{y} - 3y = 10$

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