Math, asked by reevagohel, 27 days ago

2x -3y = 10, and xy =16, find 8x^3- 2y^3

Answers

Answered by roshni542
54

Answer:

2x-3y=10

→ 2(16) - 3(16) =10. ( value of

x=16, y=16)

→ 32- 48 =10

→ 16 = 10

→  \frac{16}{10} \\  →  \frac{8}{5}

Answered by Anonymous
6

Step-by-step explanation:

2x-3y=10

2x-3y=10→ 2(16) - 3(16) =10. ( value of

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered}

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} →

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 10

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 →

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 5

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58

2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58

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