2x -3y = 10, and xy =16, find 8x^3- 2y^3
Answers
Answer:
2x-3y=10
→ 2(16) - 3(16) =10. ( value of
x=16, y=16)
→ 32- 48 =10
→ 16 = 10
Step-by-step explanation:
2x-3y=10
2x-3y=10→ 2(16) - 3(16) =10. ( value of
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered}
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} →
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 10
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 →
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 5
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58
2x-3y=10→ 2(16) - 3(16) =10. ( value ofx=16, y=16)→ 32- 48 =10→ 16 = 10\begin{gathered}→ \frac{16}{10} \\ → \frac{8}{5} \end{gathered} → 1016 → 58