Question

2x+3y=11 , 2x-4y=-24 . find the value of m which y=(m^3)x+33

Answer 1

2x+3y=11 ----eqn 1

2x-4y=24 ----eqn 2

solving both eqns by substitutions method we get

7y=35

y=5 ----eqn 2

putting the value of x in eqn 1

2x-4*5=-24

2x=-24+20

2x=-4

x=-2

m³x+33=y

m³-2+33=5

-2m³=5-33

m³=28/2

m³=14m

m=∛14

Answer 2

first solve the two equations by subtracting method w get