Question

2x+3y=11/3. 5x-7y=31/3. find zeroes​

Answer 1

Answer: Answer: The solution set are as follows: x = 170/87 and y = -7/87

Step-by-step explanation:

2x+ 3y = 11/3... (1)

5x - 7y = 31/3... (2)

• Now, multiply equation (1) by 5

5(2x+3y) = 5(11/3)

=> 10x + 15 y = 55/3... (3)

• Now, multiple equation (2) by 2

2(5x - 7y) = 2(31/3)

=>10x - 14 y = 62/3...(4)

• Now, the equations formed are:

10x + 15 y = 55/3... (3)

10x - 14 y = 62/3... (4)

• Subtract  equation (4) from (3)

29y = - 7/3

y = -7/3*29

∴ y = -7/87

• Now, put y = -7/87 in equation 1 : (2x + 3y = 11/3)

2x + 3(-7/87) = 11/3

2x - 21/87 = 11/3

2x = 11/3 + 21/87

2x =  340/87

x = 340/87*2 = 170/87

∴ x = 170/87

Answer: The solution set are as follows: x = 170/87 and y = -7/87

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