2x-3y=11 and 2x-y=-1
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Answered by
16
2x-3y=11 and 2x-y=-1
by using elimination method
y= -6
and substitute value of y in 1 eq
2x-3 (-6)=11
2x+18=11
2x=11-18
2x=-7
x=-7/2
by using elimination method
y= -6
and substitute value of y in 1 eq
2x-3 (-6)=11
2x+18=11
2x=11-18
2x=-7
x=-7/2
suryansh341:
right
thabjs
thanks
Answered by
4
2X-3Y = 11
2X = 11+3Y
X = 11+3Y/2.......(1)
2X-Y = -1
Putting the value of X in,
2X-Y = -1
2× 11+3Y/ 2 -Y = -1.
11+3Y -Y = -1
2Y = -1-11
2Y = -12
Y = -12/2 = -6
PUTTING THE VALUE OF Y IN,
X = 11-3Y/2 = 11-3×-6/2 = 11+18/2 = 29/2 = 15
X = 29/2 and Y = -6
2X = 11+3Y
X = 11+3Y/2.......(1)
2X-Y = -1
Putting the value of X in,
2X-Y = -1
2× 11+3Y/ 2 -Y = -1.
11+3Y -Y = -1
2Y = -1-11
2Y = -12
Y = -12/2 = -6
PUTTING THE VALUE OF Y IN,
X = 11-3Y/2 = 11-3×-6/2 = 11+18/2 = 29/2 = 15
X = 29/2 and Y = -6
wrong answer
do again
ya
just a second now I do with substitution method
Hey you do silly mistake check your answer
it's 11 not 12
2 is for whole not for single and at last don't take lcm
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