Math, asked by password621, 1 year ago

2x + 3y =11, x-y=1 solve the following pair of equations

Answers

Answered by abhi569
3

Answer:

Required numeric value of x and y are 14 / 5 and 9 / 5 respectively.

Step-by-step-explanation:

Given equations are 2x + 3y = 11 and x - y = 1.

Given, x - y = 1.

On adding y on both sides,

= > x - y + y = 1 + y

= > x = 1 + y

Now we can say that the algebraic value of x in terms of y is 1 + y.

Now, substituting the algebraic value of x in the other term :

= > 2x + 3y = 11

= > 2( 1 + y ) + 3y = 11

= > 2 + 2y + 3y = 11

= > 2 + 5y = 11

= > 5y = 11 - 2

= > 5y = 9

= > y = 9 / 5.

Now substituting the numeric value of y in x - y = 1 :

= > x - ( 9 / 5 ) = 1

= > x = 1 + ( 9 / 5 )

= > x = ( 5 + 9 ) / 5

= > x = 14 / 5

Hence the required numeric value of x and y are 14 / 5 and 9 / 5 respectively.

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