2x + 3y =11, x-y=1 solve the following pair of equations
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Answer:
Required numeric value of x and y are 14 / 5 and 9 / 5 respectively.
Step-by-step-explanation:
Given equations are 2x + 3y = 11 and x - y = 1.
Given, x - y = 1.
On adding y on both sides,
= > x - y + y = 1 + y
= > x = 1 + y
Now we can say that the algebraic value of x in terms of y is 1 + y.
Now, substituting the algebraic value of x in the other term :
= > 2x + 3y = 11
= > 2( 1 + y ) + 3y = 11
= > 2 + 2y + 3y = 11
= > 2 + 5y = 11
= > 5y = 11 - 2
= > 5y = 9
= > y = 9 / 5.
Now substituting the numeric value of y in x - y = 1 :
= > x - ( 9 / 5 ) = 1
= > x = 1 + ( 9 / 5 )
= > x = ( 5 + 9 ) / 5
= > x = 14 / 5
Hence the required numeric value of x and y are 14 / 5 and 9 / 5 respectively.
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