2x-3y =12
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2x +4y = -2
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- 2x-3y =12________(1)
- 2x +4y = -2_______(2)
- Value of x & y
Subtract equ(1) &equ(2)
➡ -3y - 4y = 12 + 2
➡-7x = 14
➡x = 14/(-7)
➡x = -2
Keep value of x in equ(1)
➡2 × -2 - 3y = 12
➡-3y = 12 + 4
➡-3y = 16
➡y = 16/(-3)
➡y = -16/3
- Value of x = -2
- Value of y = -16/3
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Keep Value of x & y in equ(1)
➡2 × -2 - 3 × -16/3 = 12
➡-4 + 16= 12
➡12 = 12
L.H.S. = R.H.S.
We can say that our solution is right.
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