Question

2x+3y=12
3x+2y=6
solve this two equation by substitution method

Answer 1

Answer:

X=3 and y=2 2×3+3×2= 12

X=2 and y=0. 3×2+2×0= 6

Answer 2

Given

2x + 3y = 12 (i)

3x + 2y = 6 (ii)

To Find

Value of x and y by Substitution Method

So Take (ii)eq

3x + 2y = 6

3x = 6-2y

x = (6-2y)/3 (iii)eq

Put the value of x on (i)eq

2x + 3y = 12 (i)

2(6-2y)/3 + 3y = 12

By taking LCM , we get

{2(6-2y)+9y}/3 = 12

2(6-2y)+9y = 12×3

12 - 4y + 9y = 36

12 + 5y = 36

5y = 36-12

5y = 24

y = 24/5

Now put the value of y on (iii)eq

x = (6-2y)/3 (iii)eq

x = (6 - 2×24)/3×5

x = (6 - 48)/15

x = -42/15

x = -14/15

Answer

x = -14/15 and y = 24/5