Question

2x+3y=12 and x+y = 1
find x and y using substitution method​

Answer 1

Answer:

The given equations are

⇒ x + 2y = – 1 … (i)

⇒ 2x – 3y = 12 …(ii)

From equation (i), we get

⇒ x = – 1 – 2y … (iii)

Putting x’s value in Equation (ii), we get

⇒ 2(- 1 – 2y) – 3y = 12

⇒ – 2 – 4y – 3y = 12

⇒ – 7y = 14

⇒ y = 14/- 7

⇒ y = – 2

Putting y’s value in equation (iii), we get

⇒ x = – 1 – 2y

⇒ x = – 1 – 2 × (- 2)

⇒ x = – 1 + 4

⇒ x = 3

Here, x = 3 and y = – 2.

Hence, the solution of the given equation

Step-by-step explanation:

The given equations are

⇒ x + 2y = – 1 … (i)

⇒ 2x – 3y = 12 …(ii)

From equation (i), we get

⇒ x = – 1 – 2y … (iii)

Putting x’s value in Equation (ii), we get

⇒ 2(- 1 – 2y) – 3y = 12

⇒ – 2 – 4y – 3y = 12

⇒ – 7y = 14

⇒ y = 14/- 7

⇒ y = – 2

Putting y’s value in equation (iii), we get

⇒ x = – 1 – 2y

⇒ x = – 1 – 2 × (- 2)

⇒ x = – 1 + 4

⇒ x = 3

Here, x = 3 and y = – 2.

Hence, the solution of the given equation

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