Question

2x + 3y =12 and xy +6 find 8xcube + 27ycube

Answer 1

(2x+3y)^3 = (2x)^3 + (3y)^3 + 3 (2x) (3y) ( 2x+3y)
(12)^3= (2x)^3 + (3y)^3 + 3* 6 xy (12)
1728 = (2x)^3 + (3y)^3 + 1296
(2x)^3 + (3y)^3 =432

Answer 2

Answer:

Step-by-step explanation:

(2x+3y)^3 = (2x)^3 + (3y)^3 + 3 (2x) (3y) ( 2x+3y)

(12)^3= (2x)^3 + (3y)^3 + 3* 6 xy (12)

1728 = (2x)^3 + (3y)^3 + 1296

(2x)^3 + (3y)^3 =432