2x+3y=12,xy=6,find 8x^3+27y^3
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Answer:
432
Step-by-step explanation:
2x + 3y = 12
Cubing both side, we get
(2x)³ + (3y)³ + 3.2x.3y(2x+3y) = 12³
Putting values of 2x+ 3y = 13 and xy = 6
8x³ + 27y³ + 3.2.3.(6).(12) = 12³
⇒ 8x³ + 27y³ = 12³- 9.12.12
= 12.12(12-9)
= 144*3
= 432
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