Question

2x-3y+13=0 3x-2y+12=0 Solve by substitution method

Answer 1

 Hey dear...


2x-3y+13=0;3x-2y-12=0 

Solution :

 {x,y} = {62/5,63/5} 

System of Linear Equations entered :

[1] 2x-3y+13=0 [2] 3x-2y-12=0

Equations Simplified or Rearranged :

  [1] 2x - 3y = -13   [2] 3x - 2y = 12


Solve by Substitution :

// Solve equation [2] for the variable  x  
 

[2] 3x = 2y + 12 [2] x = 2y/3 + 4

// Plug this in for variable  x  in equation [1]

  [1] 2•(2y/3+4) - 3y = -13   [1] - 5y/3 = -21   [1] - 5y = -63

// Solve equation [1] for the variable  y  

  [1] 5y = 63    [1] y = 63/5 

// By now we know this much :

  x = 2y/3+4   y = 63/5

// Use the  y  value to solve for  x  

  x = (2/3)(63/5)+4 = 62/5 

Solution :

 {x,y} = {62/5,63/5} .

Hope it helps you!!!!!!

Answer 2

Answer:

Step-by-step explanation:

2x+3y+5=0

3x-2y-12=O