Question

2x+3y=13 4x+5y=23 xor y ka maan nikalna he

Answer 1

Answer:

Given-

$2x + 3y = 13 \: \: \: \: \: - (1) \\ 4x + 5y = 23 \: \: \: \: \: - (2)$

From equation (1), we get ,

$2x + 3y = 13 \\ y = \frac{13 - 2x}{3}$

Substituting value of y in equation (2), we get,

$4x + 5y = 23 \\ 4x + 5( \frac{13 - 2x}{3} ) \\ 12x + 65 - 10x = 69 \\ 2x = 69 - 65 \\ 2x = 4 \\ x = 2$

Then Substituting value of x in equation (1), we get,

$2x + 3y = 13 \\ 2(2) + 3y = 13 \\ 4 + 3y = 13 \\ 3y = 13 - 4 \\ 3y = 9 \\ y = \frac{9}{3} \\ y = 3$

Therefore , Required solution is x=2 & y=3

Solved by Substitution Method