Question

2x+3y=13 and xy=6, then 4xsqure+9ysquer=?

Answer 1

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Answer 2

Answer:

2x+3y=13            -( 1 )

xy=6

=>x=6/y               -(2)

Eq 1 in 2

2(6/y) + 3y =13

12/y +3y =13

12 + 3$y^{2}$ = 13y

$3y^{2} -13y +12=0$

=> y = 3

As xy=6

x=2

hence $4x^{2} + 9y^{2} =4(4) +9(9) = 16+81 = 97$