2x+3y=14 & 3x-4y=4 by elimination method
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To use the elimination method,
First you will have to bring coefficient of any variable in equal terms.
2x+3y=14 ------(1)
3x-4y=4 ------(2)
Here, in the two variables X and y, There is no common factor between coefficient.
Therefore, boh will need multiplying..
Let us try to bring he coefficient of X as common.
It can be done by multiplying(1) by 3 and (2) by 2
Therefore, the new equations are,
3(2x+3y=14)=(6x+9y=42) --------(3)
2(3x-4y=4)=(6x-8y=8). --------(4)
We can clearly see that coefficient of both X's=6
Now,
Subtract (4) from (3)
(6x+9y=42)
- (6x-8y=8)
=(17y=34). y=2
We have got y.
Now putting the quantity of y in (1).
(2x+3y=14)
2x+3(2)=14
2x=8
X=4
Hence found.
Hope this helps
please mark as brainliest
First you will have to bring coefficient of any variable in equal terms.
2x+3y=14 ------(1)
3x-4y=4 ------(2)
Here, in the two variables X and y, There is no common factor between coefficient.
Therefore, boh will need multiplying..
Let us try to bring he coefficient of X as common.
It can be done by multiplying(1) by 3 and (2) by 2
Therefore, the new equations are,
3(2x+3y=14)=(6x+9y=42) --------(3)
2(3x-4y=4)=(6x-8y=8). --------(4)
We can clearly see that coefficient of both X's=6
Now,
Subtract (4) from (3)
(6x+9y=42)
- (6x-8y=8)
=(17y=34). y=2
We have got y.
Now putting the quantity of y in (1).
(2x+3y=14)
2x+3(2)=14
2x=8
X=4
Hence found.
Hope this helps
please mark as brainliest
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