Question

2x+3y=14, XY= -3 find 4x^2+9y^2​

Answer 1

Answer:

Answer:190

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y(2x + 3y)^2 = (14)^2 + 2(-3)

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y(2x + 3y)^2 = (14)^2 + 2(-3)

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y(2x + 3y)^2 = (14)^2 + 2(-3) (2x + 3y)^2 = 196 - 6

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y(2x + 3y)^2 = (14)^2 + 2(-3) (2x + 3y)^2 = 196 - 6

Answer:190(2x + 3y)^2 = 4x^2 + 9x^2 + 2×2x×3y(2x + 3y)^2 = (14)^2 + 2(-3) (2x + 3y)^2 = 196 - 6 = 190

Answer 2

Step-by-step explanation:

2x+3y=10

xy=5

4x²+9y² = ???

(2x+3y)² - 4x²+2xy+9y²

( using identity (a+b)²= a²+2ab+b² )

→ 100 = 4x² + 9y² + 2×5

→ 100-10 = 4x² + 9y²

→ 4x² + 9y² = 90