2x + 3y = 15
x + y = 6
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2x+3y=15 -(1)
x+y=6
x=6-y -(2)
substituting (2) in (1)
2(6-y) +3y=15
12-2y+3y=15
y=3
substituting y=3 in (2),
x=6-y
x=6-3
x=3
Answered by
1
Answer:
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Step-by-step explanation:
2x +3y=15____1
x+y=6-----2
multiplying equation 2 by 2
2x+2y=12 ---------3
now, subtracting Eq 3 from EQ 1
2x+3y=15
2x+2y=12
-------------------------
y=3
substituting y =3 in Eq 2
x+y=6
x+3=6
x=3
solution (x,y) =(3,3)
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