2x+3y-17=0 , 3x-2y-6=0 by substitution method
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Step-by-step explanation:
2x+3y+7=0. (1)
3x-2y-6=0. (2)
from (2) we get
x=2y+6/3. (3)
put eq (3) in eq(1)
2(2y+6/3)+3y-17=0
4y+3y=39
y=5.57
put value y in eq (2)
3x-11.14-6=0
3x=17.14
x=5.71
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