Question

2x+3y=17, 3x-2y=6
SOLVE BY USING SUBSTITUTION METHOD ​

Answer 1

$2x + 3x + 3y - 2y = 17 + 6 \\ 5x + 1y = 23 \\ 5x + y = 23 \\ x + y = 23 \div 5 \\ x + y = 4.6 \\ x = 4.6 \div 2 \\ x = 2.3 \\ y = 2.3 \\ x + y = 2.3 + 2.3 \\ x + y = 4.6$

Hope it will help

Answer 2

Answer:

x = 4 , y = 3

Step-by-step explanation:

2x + 3y = 17--------------(i)

3x - 2y = 6---------------(ii)

From eq (i)

2x = 17 - 3y

x = 17 - 3y / 2

Putting the value of x in eq (ii)

3 [ 17 - 3y / 2 ] - 2y = 6

[ 51 - 9y / 2 ] - 2y = 6

51 - 9y - 4y / 2 = 6

51 - 13y = 12

( - 13y ) = 12 - 51

( - 13y ) = ( - 39 )

y = - 39 / -13

y = 3

Putting the value of y in eq (i)

2x + 3 ( 3 ) = 17

2x + 9 = 17

2x = 17 - 9

x = 8 / 2

x = 4

Hence, the value of x is 4 and the value of y is 3.

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