Math, asked by BARANWAL7131, 1 year ago

2x-3y=19 3x-2y=21 In substitution method

Answers

Answered by Pieistasty
20
Solve equation [2] for the variable x

[2] 2x = 3y + 19

[2] x = 3y/2 + 19/2

// Plug this in for variable x in equation [1]
[1] 3•(3y/2+19/2) - 2y = 21
[1] 5y/2 = -15/2
[1] 5y = -15
// Solve equation [1] for the variable y

[1] 5y = - 15

[1] y = - 3

// By now we know this much :
x = 3y/2+19/2
y = -3

// Use the y value to solve for x
x = (3/2)(-3)+19/2 = 5
Answered by daniyashahid99
0

Answer:

value of x: 5

value of y: -3

Step-by-step explanation:

Equation 1: 2x-3y=19

Equation 1: 2x-3y=19Equation 2: 3x-2y=21

Using equation 2 for x variable -

2x = 3y+19

x = 3y/2 + 19/2

Put this value of x into equation 1

3(3y/2+19/2)-2y = 21

5y/2 = -15/2

5y = -15

y = -3

Using the values if above variables, we can say:

x = 3y/2+19/2

put the value of y in this equation

x = (3/2)(- 3) + 19/2 = 5

value of x: 5

value of y: -3

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