2x-3y=19 3x-2y=21 In substitution method
Answers
Answered by
20
Solve equation [2] for the variable x
[2] 2x = 3y + 19
[2] x = 3y/2 + 19/2
// Plug this in for variable x in equation [1]
[1] 3•(3y/2+19/2) - 2y = 21
[1] 5y/2 = -15/2
[1] 5y = -15
// Solve equation [1] for the variable y
[1] 5y = - 15
[1] y = - 3
// By now we know this much :
x = 3y/2+19/2
y = -3
// Use the y value to solve for x
x = (3/2)(-3)+19/2 = 5
[2] 2x = 3y + 19
[2] x = 3y/2 + 19/2
// Plug this in for variable x in equation [1]
[1] 3•(3y/2+19/2) - 2y = 21
[1] 5y/2 = -15/2
[1] 5y = -15
// Solve equation [1] for the variable y
[1] 5y = - 15
[1] y = - 3
// By now we know this much :
x = 3y/2+19/2
y = -3
// Use the y value to solve for x
x = (3/2)(-3)+19/2 = 5
Answered by
0
Answer:
value of x: 5
value of y: -3
Step-by-step explanation:
Equation 1: 2x-3y=19
Equation 1: 2x-3y=19Equation 2: 3x-2y=21
Using equation 2 for x variable -
2x = 3y+19
x = 3y/2 + 19/2
Put this value of x into equation 1
3(3y/2+19/2)-2y = 21
5y/2 = -15/2
5y = -15
y = -3
Using the values if above variables, we can say:
x = 3y/2+19/2
put the value of y in this equation
x = (3/2)(- 3) + 19/2 = 5
value of x: 5
value of y: -3
Similar questions