Question

(2x - 3y-2)(2x + y-5)​

Answer 1

Answer:

(2x - 3y - 2 ) ( 2x + y - 5 ) = 0

= $4x {}^{2} + 2xy - 10x - 6xy - 3y {}^{2} + 15y - 4x - 2y + 10$ = 0

= $4x {}^{2} - 3y {}^{2} - 4xy - 14x + 13y + 10$ = 0

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