Question

2x^3y^2-4x-3xy-5(x^2y^2-x^2) when X=5,y=2
find the value of the following expression​

Answer 1

To find : value of given expression ,  $2x^{3} y^{2} -4x-3xy-5(x^{2} y^{2}-x^{2})$  

Given : $x = 5$   , $y = 2$

Solution :

• According to question we have find the value of given expression

      $2x^{3} y^{2} -4x-3xy-5(x^{2} y^{2}-x^{2})$ by substituting the given value of $x$ and $y$ .

• Therefore on substituting the values we get ,
•  $2x^{3} y^{2} -4x-3xy-5(x^{2} y^{2}-x^{2})$

         $= 2 (5 )^{3}(2 )^{2} - 4(5 )-3(5 )(2 ) - 5 ((5)^{2} (2)^{2} - (5)^{2} ) \\= 2(125)(4)-20 - 30-5((25)(4)-25) \\= 2500 - 20-30-5 (100-25 )\\= 2500-20-30-5(75 )\\= 2500-20-30-375 \\=2075$

Hence , the value of expression  $2x^{3} y^{2} -4x-3xy-5(x^{2} y^{2}-x^{2})$ will be $2075$ .