Question

2x+ 3y = 2
$\sqrt{6xy}$




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Answer 1

2x+ 3y = 2

(2x+ 3y)² = 2²

we know that (a+b)² = a² + b²+ 2ab

so, 4x² + 9y² + 2×6xy = 4

2×6xy = 4 - 4x² - 9y²

6xy = (4 - 4x² - 9y²)/2

√6xy = √[(4 - 4x² - 9y²)/2]

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