2x-3y=2,x+2y=8, find by substitution method
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0
Answer:
x=4
y=2
Step-by-step explanation:
x+2y=8
x=8-2y
2x-3y=2
2(8-2y)-3y=2
16-4y-3y=2
16-2=7y
14=7y
y=2
x=8-2y
x=8-4
x=4
Answered by
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Given :-
2x - 3y = 2
x + 2y = 8
Solution :-
2x - 3y = 2 ........eq( 1 )
x + 2y = 8
x = 8 - 2y ...........eq( 2 )
Now , Subsitute eq( 2) in eq( 1 )
2x - 3y = 2
2( 8 - 2y ) - 3y = 2
16 - 4y - 3y = 2
16 - 7y = 2
-7y = 2 - 16
- 7y = -14
y = -14/ -7
y = 2
Now ,Subsitute the value of y in eq( 2)
x = 8 - 2y
x = 8 - 2 ( 2)
x = 8 - 4
x = 4
Hence , The value of x and y is 2 and 4
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