2x+3y=2 ; x-y/2=1/2 solve simultaneous equation
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2x + 3y = 2(equation 1)
(x - y)/2 = 1/2
x - y = 1 (equation 2)
1(2x + 3y = 2)
2(x - y = 1)
2x + 3y = 2
2x - 2y = 2
Subtracting equation 2 from 1
2x + 3y = 2
- 2x + 2y = - 2
5y = 0
y = 0
x - y = 1
x - 0 = 1
x = 1
The values of x and y are 1 and 0.
(x - y)/2 = 1/2
x - y = 1 (equation 2)
1(2x + 3y = 2)
2(x - y = 1)
2x + 3y = 2
2x - 2y = 2
Subtracting equation 2 from 1
2x + 3y = 2
- 2x + 2y = - 2
5y = 0
y = 0
x - y = 1
x - 0 = 1
x = 1
The values of x and y are 1 and 0.
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