2x+3y=2;x-y/2=1/2 solve this pls give answers
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Answer: x=5/8 and y=1/4
Step-by-step explanation:
according to Cramer's rule,
when two equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 .
then, \frac{x}{b_1c_2-b_2c_1}=\frac{-y}{a_1c_2-a_2c_1}=\frac{1}{a_1b_2-b_1a_2}
Given, 2x + 3y - 2 = 0
x - y/2 = 1/2
=> 2x - y = 1
=> 2x -y - 1 = 0
x/{3 × (-1) - (-2) × (-1)} = -y/{2 × (-1) - (-2) × 2} = 1/{2 × (-1) - 3 × 2 }
=> x/(-3 - 2) = -y/(-2 + 4) = 1/(-2 - 6)
=> x/(-5) = -y/2 = /1-8
=> x = 5/8 and y = 1/4
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