2x+3y=20
7x+2y=53
solve by substitute
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Answer:
2x+3y=20
2x=20-3y
X=20-3y/2
putting the value of X in eq ii
7(20-3y/2)+2y=53
(20-3y/2)+2y=53-7
20-3y/2+2y=46
20-3y+4y/2=46
20+y=46*2
20+y=92
y=92/20
y=23/5
substituting the value of y in eq I
2x+3*23/5=20
2x+69/5=20
2x+69=20*5
2x+69=100
2x=100-69
2x= 31
X=31/2
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